please help..
i tried but cant prove it.. much appreciated if you help
woops i forgot the identity = sinθ+cosθ
(1 + 2sinx*cosx) / (sinx + cosx).
use 1 = sin^2(x) + cos^2(x)
(1 + 2sinx*cosx) / (sinx + cosx)
= (sin^2x + cos^2x + 2sinx*cosx) / (sinx + cosx)
= (sinx + cosx)^2 / (sinx + cosx)
= sinx + cosx.
How can we prove it. You don't have an identity but only an expression.
Please complete the identity
sin^2x+cos^2x+2sinxcosx/sinx+cosx
=(sinx+cosx)^2/sinx+cosx
=sinx+cosx
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
(1 + 2sinx*cosx) / (sinx + cosx).
use 1 = sin^2(x) + cos^2(x)
(1 + 2sinx*cosx) / (sinx + cosx)
= (sin^2x + cos^2x + 2sinx*cosx) / (sinx + cosx)
= (sinx + cosx)^2 / (sinx + cosx)
= sinx + cosx.
How can we prove it. You don't have an identity but only an expression.
Please complete the identity
sin^2x+cos^2x+2sinxcosx/sinx+cosx
=(sinx+cosx)^2/sinx+cosx
=sinx+cosx