solve in the interval of [0, 2π) or [0, 360 degrees)
sin (4Ө) = - √3 / 2
4Ө = 240° ,300° ,600° ,660° ,960° ,1020° ,1320° ,1380°
Ө = 60° , 75° , 150° , 165° , 240° , 255° , 330° , 345°
2sin4Î + â3 = 0? solve in the interval of [0, 2Ï) or [0, 360 degrees)
sin4theta = -sqrt(3)/2 = -0.8660
so theta will lie in the 3rd and 4th quadrants, i.e. between 180 & 270 and 270 & 360 degrees
4theta = -60 degrees
theta = -15 degrees
theta = 195 and 345 degrees
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Verified answer
sin (4Ө) = - √3 / 2
4Ө = 240° ,300° ,600° ,660° ,960° ,1020° ,1320° ,1380°
Ө = 60° , 75° , 150° , 165° , 240° , 255° , 330° , 345°
2sin4Î + â3 = 0? solve in the interval of [0, 2Ï) or [0, 360 degrees)
sin4theta = -sqrt(3)/2 = -0.8660
so theta will lie in the 3rd and 4th quadrants, i.e. between 180 & 270 and 270 & 360 degrees
4theta = -60 degrees
theta = -15 degrees
theta = 195 and 345 degrees
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