Verified answer

It can be. The best way to start is to factor out b so you have b(2b^2 + 14b + 24) and then factor the part in parentheses like a normal quadratic equation.

well to find the answer you must look within. you must become the awareness of the polynomial function. only then will it factor itself for you and you will find out that factoring itself is an illusion.

2b³ + 14b²+24b = b(2b²+14b + 24) = 2b(b²+7b + 12) = 2b(b + 4)(b + 3)

Not sure why the previous three didn't finish the problem!

2b(b^2 + 7b + 12) = 2b(b + 3)(b + 4)

To factor you need to find common factor in the equation.

So in that equation, the common factor is 2b (you can divide each of them by 2b)

So once you do that, you take that out of the equation and put it in brackets outside.

EX: 2b(2b³ + 14b²+24b)

then you divide the numbers in the brackets by the factor you took out. People usually do both of them in 1 step but since im showing you, i will do it in 2.

EX: Ok so first we had 2b³ + 14b²+24b

Then we took 2b out : 2b(2b³ + 14b²+24b)

We have to divide the numbers in the bracket by 2b. If you do that you will get this:

2b(b² + 7b+12)

That is your answer.

To check, you multiply it and if you get the same answer its right.

2b x b² = 2b³

2b x 7b = 14b²

2b x 12 = 24b

So the answer is right.

Hope I helped!

(the quadratic equation way that the other guy posted is also another way to do this but much more complicated)

It can be factored to 2b(b2+7b+12)

b2= b squared

2b(b^2+7b+12)