Verified answer

0.107

the top reduces to one and the denominator is just t^2. So you have the integral of t^-2 from -7 to -4. When you integrate you increase the power by one and divide the whole term by that number. In this case, the power is increased to -1, so you have to divide by -1. you now have -t^-1 from -7 to -4. Plug in your values and you get 3/28.

the integral of ∫......(1/t)^2 dt is -1/t +c (ignore c as this is a definite integral)

substitute -4 and get an answer,subtract it from the answer you get from subbing -7. that is the definite integral.