The work done equals
∫c F · dr
= ∫ <xy, 6, 5x> · r'(t) dt
= ∫(t = 0 to π/18) <cos(9t) sin(9t), 6, 45 cos(9t)> · <-9 sin(9t), 9 cos(9t), 1> dt
= ∫(t = 0 to π/18) [-9 sin^2(9t) cos(9t) + 99 cos(9t)] dt
= [(-1/3) sin^3(9t) + 11 sin(9t)] {for t = 0 to π/18}
= 32/3.
I hope this helps!
so integrate F dot dr.......about 0.7 [ units ? ]
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Answers & Comments
The work done equals
∫c F · dr
= ∫ <xy, 6, 5x> · r'(t) dt
= ∫(t = 0 to π/18) <cos(9t) sin(9t), 6, 45 cos(9t)> · <-9 sin(9t), 9 cos(9t), 1> dt
= ∫(t = 0 to π/18) [-9 sin^2(9t) cos(9t) + 99 cos(9t)] dt
= [(-1/3) sin^3(9t) + 11 sin(9t)] {for t = 0 to π/18}
= 32/3.
I hope this helps!
so integrate F dot dr.......about 0.7 [ units ? ]