Calculate the standard free-energy change for the following reaction at 25 °C?
The equation is 2Au^3+ + 3Cr ----> 2Au + 3Cr^2+
I am using the equation deltaG = -nFE
Au3+ + 3e- ------> Au E = 1.498
Cr2+ + 2e- ------> Cr E = -0.407
For n I have 6 electrons, and for E I have 1.905. My answer is -1102.995 but my homework says it is incorrect. What am I doing wrong?
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E = 1,091 V
deltaG = -nFE = -631,6 kJ/mol
youre answer is wrong