Calculate the freezing point of a solution that contains 24.14 grams of a non-volatile solute in 186 grams of water. ?
The molar mass of the solute is 120 g/mol, and the freezing point depression constant for water is 1.86 oC per unit molality.
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Supposing the solute is also a non-electrolyte:
(24.14 g) / (120 g/mol) / (0.186 kg) = 1.0815 mol/kg = 1.0815 m
(1.0815 m) x (1.86 °C/m) = 2.01°C change
0°C - 2.01°C = - 2.01°C