q = mcΔT
ΔT = -82.5°C - ( -15.7°C ) = -66.8°C
ΔT = -66.8°C = -66.8K
q = ( 2.25 g )( 2.087 J/g·K )( -66.8K )
q = -313.7 J of heat is released
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Verified answer
q = mcΔT
ΔT = -82.5°C - ( -15.7°C ) = -66.8°C
ΔT = -66.8°C = -66.8K
q = ( 2.25 g )( 2.087 J/g·K )( -66.8K )
q = -313.7 J of heat is released