calculate ΔH for the reaction NO+O2--> NO2?

Given the data:

2O2-->3O2 ΔH=-427 kj

O2-->2O ΔH= +495 kj

NO+O3-->NO2+O2 ΔH= -199 kj

Can you help me better understand how to figure this out and show the steps you take to get the answer

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