Calculate cos(ᴨ/12) and sin(ᴨ/12) . Properties listed below.?
Use these properties to calculate these
sin²θ = 1 - cos2θ/2 and
cos²θ = 1 + cos2θ/2
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Use these properties to calculate these
sin²θ = 1 - cos2θ/2 and
cos²θ = 1 + cos2θ/2
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Verified answer
cos²θ = 1/2[1 + cos(2θ) ]
cos^2( Π/12) = 1/2 [ 1 + cos(Π/6) ]
= (1/2)(1 + √3/2)
= 1/4(2 + √3)
cos( Π/12) = SQRT [1/4(2 + √3) ]
= (1/2)√(2 +√3)
similarly
sin( Π/12) = = (1/2)√(2 -√3)