y(x) = -((1 - i√(3)) e^( - (2 C) / 3) x^2) / (12 (6√(3)√(27 e^(4 C) x^2
- e^(2 C) x^4) - 54 e^(2 C) x + x^3)^(1/3)) - 1/12 (1 + i√(3)) e^( - (2 C) / 3) (6 √(3)√(27 e^(4 C) x^2 - e^(2 C) x^4) - 54 e^(2 C) x + x^3)^(1/3) - 1/6 e^( - (2 C) / 3) (6 e^((2 C) / 3) - 1) x
Answers & Comments
Verified answer
...
dx+dy=(x+y)(1+(y/x))^2 (xdy-ydx)
y(x) = -((1 - i√(3)) e^( - (2 C) / 3) x^2) / (12 (6√(3)√(27 e^(4 C) x^2
- e^(2 C) x^4) - 54 e^(2 C) x + x^3)^(1/3)) - 1/12 (1 + i√(3)) e^( - (2 C) / 3) (6 √(3)√(27 e^(4 C) x^2 - e^(2 C) x^4) - 54 e^(2 C) x + x^3)^(1/3) - 1/6 e^( - (2 C) / 3) (6 e^((2 C) / 3) - 1) x
WolframAlpha
Suerte
https://www.youtube.com/watch?v=Y5zCUpQy6Rw
NI IDEA
no..............................creo
Hola
Si interviniera x^2 multiplicando
por ejemplo
x^2 (dx+dy) =(x+y)(1+(y/x))^2 (xdy-ydx)
la solución sería
d(ln(x + y)) = d atan(y/x)
ln(x + y) - atan(x/y) = k
*****************************