Sea f(x)=-x^2+ax+b.Encontrar todos los valores de a y b tales que la parabola sea tangente a las rectas y=x+1, y=-2x+1.
f(x) = - x² + ax + b ← this is the parábola
The line is tangent to the curve. That means that there is only one common point between the line and the parabola.
y = x + 1 ← this is the line (ℓ1)
y = - x² + ax + b
y = y
x + 1 = - x² + ax + b
x + 1 + x² - ax - b = 0
x² + x.(1 - a) + (1 - b) = 0
Polynomial like: ax² + bx + c, where:
A = 1
B = (1 - a)
C = (1 - b)
Δ = B² - 4AC (discriminant)
Δ = (1 - a)² - 4.(1 - b)
Δ = 1 - 2a + a² - 4 + 4b
Δ = a² - 2a + 4b - 3 → only one point, → Δ = 0
a² - 2a + 4b - 3 = 0 ← first condition → equation (1)
y = - 2x + 1 ← this is the line (ℓ2)
- 2x + 1 = - x² + ax + b
- 2x + 1 + x² - ax - b = 0
x² + x.(- 2 - a) + (1 - b) = 0
B = (- 2 - a)
Δ = (- 2 - a)² - 4.(1 - b)
Δ = 4 + 4a + a² - 4 + 4b
Δ = a² + 4a + 4b → only one point, → Δ = 0
a² + 4a + 4b = 0 ← second condition → equation (2)
Then you calciulate (2) - (1)
(a² + 4a + 4b) - (a² - 2a + 4b - 3) = 0 - 0
a² + 4a + 4b - a² + 2a - 4b + 3 = 0
6a + 3 = 0
6a = - 3
a = - 3/6
→ a = - 1/2
Recall (2): a² + 4a + 4b = 0
(- 1/2)² + [4 * (- 1/2)] + 4b = 0
(1/4) - 2 + 4b = 0
4b = 2 - (1/4)
4b = 7/4
→ b = 7/16
f(x) = - x² + ax + b
f(x) = - x² - (1/2).x + (7/16)
Hola
Recta tangente en punto (xo,yo)
yo = xo^2 + a xo + b
y - yo = (2 xo + a) (x - xo)
y = xo^2 + a xo + b - (2 xo^2 + a xo) + (2 xo + a) x
y = (2 xo + a) x + (b - xo^2)
*******************************
Rectas tangentes
Primera recta tangente
y = x + 1
1) 2 xo + a = 1
2) b - xo^2 = 1
de 1)
xo = (1 - a)/2
en 2)
b - ((1 - a)/2)^2 = 1
3) 4 b - (1 - a)^2 = 4
*************************
Segunda recta tangente
y = -2 x + 1
4) 2 x1 + a = -2
5) b - x1^2 = 1
de 4)
x1 = (-2 - a)/2
en 5)
b - ((-2 - a)/2)^2 = 1
6) 4 b - (2 + a)^2 = 4
de 3) y 6)
(1 - a)^2 = (2 + a)^2
1 - 2 a + a^2 = 4 + 4 a + a^2
6 a = -3
a = -1/2
**********
en 6)
4 b - (2 - (1/2))^2 = 4
4 b - (3/2)^2 = 4
4 b = 4 + (9/4)
4 b = 25/4
b = 25/16
************
parábola
y = x^2 - (1/2) x + (25/16)
**********************************
Saludos
consulta al profesor poztnagel
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
f(x) = - x² + ax + b ← this is the parábola
The line is tangent to the curve. That means that there is only one common point between the line and the parabola.
y = x + 1 ← this is the line (ℓ1)
y = - x² + ax + b
y = y
x + 1 = - x² + ax + b
x + 1 + x² - ax - b = 0
x² + x.(1 - a) + (1 - b) = 0
Polynomial like: ax² + bx + c, where:
A = 1
B = (1 - a)
C = (1 - b)
Δ = B² - 4AC (discriminant)
Δ = (1 - a)² - 4.(1 - b)
Δ = 1 - 2a + a² - 4 + 4b
Δ = a² - 2a + 4b - 3 → only one point, → Δ = 0
a² - 2a + 4b - 3 = 0 ← first condition → equation (1)
y = - 2x + 1 ← this is the line (ℓ2)
y = - x² + ax + b
y = y
- 2x + 1 = - x² + ax + b
- 2x + 1 + x² - ax - b = 0
x² + x.(- 2 - a) + (1 - b) = 0
Polynomial like: ax² + bx + c, where:
A = 1
B = (- 2 - a)
C = (1 - b)
Δ = B² - 4AC (discriminant)
Δ = (- 2 - a)² - 4.(1 - b)
Δ = 4 + 4a + a² - 4 + 4b
Δ = a² + 4a + 4b → only one point, → Δ = 0
a² + 4a + 4b = 0 ← second condition → equation (2)
Then you calciulate (2) - (1)
(a² + 4a + 4b) - (a² - 2a + 4b - 3) = 0 - 0
a² + 4a + 4b - a² + 2a - 4b + 3 = 0
6a + 3 = 0
6a = - 3
a = - 3/6
→ a = - 1/2
Recall (2): a² + 4a + 4b = 0
(- 1/2)² + [4 * (- 1/2)] + 4b = 0
(1/4) - 2 + 4b = 0
4b = 2 - (1/4)
4b = 7/4
→ b = 7/16
f(x) = - x² + ax + b
f(x) = - x² - (1/2).x + (7/16)
Hola
Recta tangente en punto (xo,yo)
yo = xo^2 + a xo + b
y - yo = (2 xo + a) (x - xo)
y = xo^2 + a xo + b - (2 xo^2 + a xo) + (2 xo + a) x
y = (2 xo + a) x + (b - xo^2)
*******************************
Rectas tangentes
Primera recta tangente
y = x + 1
1) 2 xo + a = 1
2) b - xo^2 = 1
de 1)
xo = (1 - a)/2
en 2)
b - ((1 - a)/2)^2 = 1
3) 4 b - (1 - a)^2 = 4
*************************
Segunda recta tangente
y = -2 x + 1
4) 2 x1 + a = -2
5) b - x1^2 = 1
de 4)
x1 = (-2 - a)/2
en 5)
b - ((-2 - a)/2)^2 = 1
6) 4 b - (2 + a)^2 = 4
*************************
de 3) y 6)
(1 - a)^2 = (2 + a)^2
1 - 2 a + a^2 = 4 + 4 a + a^2
6 a = -3
a = -1/2
**********
en 6)
4 b - (2 - (1/2))^2 = 4
4 b - (3/2)^2 = 4
4 b = 4 + (9/4)
4 b = 25/4
b = 25/16
************
parábola
y = x^2 - (1/2) x + (25/16)
**********************************
Saludos
consulta al profesor poztnagel