23 km/h = 6.6666m/s
apply kinetic energy = 1/2*mass*velocity^2
Ek = 1/2*(2*10^5)*6.66666^2
Ek = 4,444,435.5J
Now apply kinetic energy = 1/2*m*v^2 for the car
4,444,435.5 = 1/2*1900*v^2
4,444,435.5 = 950v^2
v^2 = 4678.35
v = 68.398 m/s
So the compact car must go at 68.398 m/s.
Hope this helps
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Verified answer
23 km/h = 6.6666m/s
apply kinetic energy = 1/2*mass*velocity^2
Ek = 1/2*(2*10^5)*6.66666^2
Ek = 4,444,435.5J
Now apply kinetic energy = 1/2*m*v^2 for the car
4,444,435.5 = 1/2*1900*v^2
4,444,435.5 = 950v^2
v^2 = 4678.35
v = 68.398 m/s
So the compact car must go at 68.398 m/s.
Hope this helps