Verified answer

This one is easy. For conversions between H and OH, all you need to know that Kw=H x OH where Kw is the constant of water. That constant is 1 x 10^-14. So just solve for OH

1 x 10^-14 = 1.5 x 10^-5 X OH

divide 1 x 10^-14 by 1.5x10^-5 to get the answer

At 25°C, a solution has [H+] = 1.5 x 10-5. What is [OH-] for this solution?

As 2 water molecules collide with each other, an H+ is attracted from one of the water molecules to the other, as shown below.

H2O + H2O → H3O+1 + OH-1

The concentration of H3O+1 ions and OH-1 ions in an aqueous solution is determined by the equation below.

[H3O+1] * [OH-1] = 1 * 10^-14

[H3O+1] is the same as [H+]

(1 * 10^-5) * [OH-1] = 1 * 10^-14

[OH-1] = (1 * 10^-14) ÷ (1 * 10^-5) = 1 * 10^-9

I hope this helps!!

Remember that 14 = pH + pOH

And pH = -log [H+]

Does that help?

It is more complicated than that, but I am assuming this is in water and you are in grade 10. Wait until third year physical chemistry ;)