Evaluate ∫x^2 + 3x - 10 / x-2 dx.
I assume you mean ∫ (x^2 + 3x - 10) dx / (x-2). Then,
∫ (x^2 + 3x - 10) dx / (x-2)
= ∫ (x + 5) dx
= x²/2 + 5x + C
(assuming that x is not 2)
First reduce the fraction:
(x^2+3x-10)/(x-2) = (x+5)
integral of x+5 is x^2 /2+5x +C
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I assume you mean ∫ (x^2 + 3x - 10) dx / (x-2). Then,
∫ (x^2 + 3x - 10) dx / (x-2)
= ∫ (x + 5) dx
= x²/2 + 5x + C
(assuming that x is not 2)
First reduce the fraction:
(x^2+3x-10)/(x-2) = (x+5)
integral of x+5 is x^2 /2+5x +C