Verified answer

Similar with other questions...

λ(x² - x) + 2(x + 1) = 0 => λx² + (2 - λ)x + 2 = 0

α + β = (λ - 2)/λ = 1 - 2/λ, αβ=2/λ

α/β + β/α

= [(α + β)² - 2αβ]/αβ

= [(1 - 2/λ)² - 4/λ]/(2/λ)

= λ(1 - 8/λ + 4/λ²)/2

= (λ - 8 + 4/λ)/2

= λ/2 + 2/λ - 4

60c54864e37e39fd7ffccfe91151c2eand60c54864e37e39fd7ffccfe91151c2e are the roots of60c54864e37e39fd7ffccfe91151c2e^260c54864e37e39fd7ffccfe91151c2e p60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e1 = 0 60c54864e37e39fd7ffccfe91151c2e? = -p, and x - (?+?)][x - (?+?) = a million The equation with the roots 60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2eand60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e is [x - (?+?)][x - (?+?)-60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e][x - (?+?)][x - (?+?)-60c54864e37e39fd7ffccfe91151c2e?60c54864e37e39fd7ffccfe91151c2e)] =x - (?+?)][x - (?+?)^2 -60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e?+260c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e(60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e?+260c54864e37e39fd7ffccfe91151c2e= 260c54864e37e39fd7ffccfe91151c2e - p60c54864e37e39fd7ffccfe91151c2e(60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e= 60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e(60c54864e37e39fd7ffccfe91151c2e?60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e?^2 =x - (?+?)][x - (?+?)^2 - p60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e1 so the equation is60c54864e37e39fd7ffccfe91151c2e^2 -60c54864e37e39fd7ffccfe91151c2e260c54864e37e39fd7ffccfe91151c2e- p60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e^2 - p60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e1 ~~~~~~~~~~~~~~~~~~~~ probably a mis-replica, because you've written a similar equation60c54864e37e39fd7ffccfe91151c2e^260c54864e37e39fd7ffccfe91151c2e p60c54864e37e39fd7ffccfe91151c2e60c54864e37e39fd7ffccfe91151c2e1 = 0, without consisting of q So, have not tried that area, yet you likely use a similar theory,60c54864e37e39fd7ffccfe91151c2esum of the roots, fabricated from roots60c54864e37e39fd7ffccfe91151c2e manipulation60c54864e37e39fd7ffccfe91151c2eJust examine different submit and reported that's going to were q. sturdy answer already given Regards - Ian

Can you tell us what the context is... ?

Solve for the roots:

x = ((2-lambda) +/- sqrt(lambda^2 -12 lambda + 4))/(2 lambda)

and then simply plug in the two roots to alpha/beta + beta/alpha =

(alpha^2 + beta^2)/(alpha beta) =

-4 + 2/lambda + lambda/2

(λ^2)-(4*λ)+2