Las ecuaciones son:
1) x y´=y+x
2) (x-y)dx+(x-y+1)dy=0
3) y^2+x^2 / 2xy
4) dy/dx= x/y + y/x
5) xy´-y=x^2e^x
se los agradecería mucho :3
Hola
1) x y´= y + x
x dy = y dx + x dx
x dy - y dx = x dx
(x dy - y dx)/x^2 = x dx / x^2 = dx/x
d (y/x) = d(ln(x))
y/x = k + ln(x)
y = k x + x ln(x)
********************
u = x - y
du = dx - dy
dy = dx - du
u dx + (u - 1) (dx - du) = 0
(2 u - 1) dx = (u - 1) du
2 dx = (u - (1/2) - (1/2)) du/(u - (1/2))
2 dx = du - (1/2) d( ln(u - (1/2)) )
2 x = u - (1/2) ln(u - (1/2) ) + C
2 x = 2 x - 2 y - (1/2) ln(x - y - (1/2)) + C
4 y + ln( x - y - (1/2)) = C'
Falta el diferencial, la igualdad....
u = y/x
y = u x
dy = u dx + x du
u dx + x du = ( (1/u) + u) dx
x du = dx/u
u du = dx/x
(1/2) u^2 = ln(x) + c
(1/2) (y/x)^2 = ln(x) + c
(x y' - y)/x^2 = e^x
(y/x)' = e^x
y/x = e^x + c
y = x e^x + c x
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Hola
1) x y´= y + x
x dy = y dx + x dx
x dy - y dx = x dx
(x dy - y dx)/x^2 = x dx / x^2 = dx/x
d (y/x) = d(ln(x))
y/x = k + ln(x)
y = k x + x ln(x)
********************
2) (x-y)dx+(x-y+1)dy=0
u = x - y
du = dx - dy
dy = dx - du
u dx + (u - 1) (dx - du) = 0
(2 u - 1) dx = (u - 1) du
2 dx = (u - (1/2) - (1/2)) du/(u - (1/2))
2 dx = du - (1/2) d( ln(u - (1/2)) )
2 x = u - (1/2) ln(u - (1/2) ) + C
2 x = 2 x - 2 y - (1/2) ln(x - y - (1/2)) + C
4 y + ln( x - y - (1/2)) = C'
3) y^2+x^2 / 2xy
Falta el diferencial, la igualdad....
4) dy/dx= x/y + y/x
u = y/x
y = u x
dy = u dx + x du
u dx + x du = ( (1/u) + u) dx
x du = dx/u
u du = dx/x
(1/2) u^2 = ln(x) + c
(1/2) (y/x)^2 = ln(x) + c
5) xy´-y=x^2e^x
(x y' - y)/x^2 = e^x
(y/x)' = e^x
y/x = e^x + c
y = x e^x + c x