Algebra Homework: 4√9xy^3 * 3√54x^4y^2 and 3√12) / 12?
The problem is 4√9xy^3) * 3√54x^4 y^2)
The first is to the fourth root and the second to the third.
Second problem is:
3√12) <--- to the third root
--------- <---- fraction
√10
Showing the steps would also be really helpful to me.
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4√9xy^3 * 3√54x^4y^2
= 12√3²√x√y^3 * √3²6√x^4√y^2
= 12*3*3*x²*y²√6*√x√y
= 108x²y²√6xy
(3√12) / 12
= 3√(4*3)/12
= (6√3)/12
= ½ √3
3√12
--------
√10
3√(4*3)
-----------
√10
6√3…..√10
------ * --------
√10…..√10
6√30….3√30
------- = -------
10……….5