A soma do dobro de um numero com a metade de outro da 53. calcule esses numeros, sabendo que a diferença entre o primeiro numero e o triplo do segundo é igual a sete
{2x+y/2=53...........(*6)
{x - 3y=7
{12x+3y=318
------------------
13x=325
x=325/13= 25 >>>
x-3y=7
3y=x-7
3y=25-7
3y=18
y=6 >>>>>>>>
2x + y/2 = 53
x - 3y = 7 ---> x = 7 + 3y
2(7 + 3y) + y/2 = 53
14 + 6y + y/2 = 53 MMC = 2
28 + 12y + y = 106
13y = 106 - 28
13y = 78
y = 78/13
y = 6
x = 7 + 3y
x = 7 + 3*6
x = 7 + 18
x = 25
2x+y/2=53
4x+y=106
x-3y=7,---->x=7+3y
4(7+3y)+y=106
28+12y+y=106
13y=106-28
13y=78
y=78/13
y=6
x=7+3y
x=7+3*6
x=7+18
x=25
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{2x+y/2=53...........(*6)
{x - 3y=7
{12x+3y=318
{x - 3y=7
------------------
13x=325
x=325/13= 25 >>>
x-3y=7
3y=x-7
3y=25-7
3y=18
y=6 >>>>>>>>
2x + y/2 = 53
x - 3y = 7 ---> x = 7 + 3y
2(7 + 3y) + y/2 = 53
14 + 6y + y/2 = 53 MMC = 2
28 + 12y + y = 106
13y = 106 - 28
13y = 78
y = 78/13
y = 6
x = 7 + 3y
x = 7 + 3*6
x = 7 + 18
x = 25
2x+y/2=53
x-3y=7
4x+y=106
x-3y=7,---->x=7+3y
4(7+3y)+y=106
28+12y+y=106
13y=106-28
13y=78
y=78/13
y=6
x=7+3y
x=7+3*6
x=7+18
x=25