Sabendo que a tgx= -12/5, e que pi/2<x<pi, calcule:
a) senx
b) secx
c) cossecx
d) cotgx
e) cosx
obrigada ;)
Ola Luisa
tg(x) = -12/5
tg(x) = sen(x)/cos(x) = -12/5
5sen(x) = -12cos(x)
25sen²(x) = 144cos²(x)
25sen²(x) - 144cos²(x) = 0
sen²x) + cos²(x) = 1
144sen²x) + 144cos²(x) = 144
169sen²(x) = 144
sen²(x) = 144/169
sen(x) = 12/13
cos²(x) = 25/169
cos(x) = -5/13
a) sen(x) = 12/13
b) sec(x) = -13/5
c) cossec(x) = 13/12
d) cotg(x) = -12/5
e) cos(x) = -5/13
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Answers & Comments
Ola Luisa
tg(x) = -12/5
tg(x) = sen(x)/cos(x) = -12/5
5sen(x) = -12cos(x)
25sen²(x) = 144cos²(x)
25sen²(x) - 144cos²(x) = 0
sen²x) + cos²(x) = 1
144sen²x) + 144cos²(x) = 144
169sen²(x) = 144
sen²(x) = 144/169
sen(x) = 12/13
cos²(x) = 25/169
cos(x) = -5/13
a) sen(x) = 12/13
b) sec(x) = -13/5
c) cossec(x) = 13/12
d) cotg(x) = -12/5
e) cos(x) = -5/13
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