After n years, the price of a house is $30000(1.2)ⁿ. Find the minimum number of years .....?
After n years, the price of a house is $30000(1.2)ⁿ. Find the minimum number of years for the price to exceed $72000
More Questions From This User See All
Answers & Comments
Verified answer
1.2^n = 72/30
n log(1.2) = log(72/30)
n = log(72/30) / log(1.2)
n = ln (72 / 30) / ln ( 1.2)
n = 4.8