After flying for 16 min in a wind blowing 35 km/h at an angle of 25° south of east, an airplane pilot is over?
After flying for 16 min in a wind blowing 35 km/h at an angle of 25° south of east, an airplane pilot is over a town that is 58 km due north of the starting point. What is the speed of the airplane relative to the air, in km/h?
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the resultant is 58 km / 16 min * 60 min/h = 217.5 km/h N
draw this to scale and the wind vector of 35 @ 25 S of E
complete the parallelogram with the resultant as the diagonal
then compute the other side for v of plane
217.5 @ 0 deg - 35 @ 115 deg = 234 @ -7.78 deg or 234 km/h, 7.8 deg W of N
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