A worker stands still on a roof sloped at an angle of 28° above the horizontal.?
A worker stands still on a roof sloped at an angle of 28° above the horizontal. He is prevented from slipping by a static frictional force of 450 N. Find the mass of the worker.
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We can write weight component w = mg sin(theta) = k mg cos(theta) = f friction force. So m = f/g sin(theta) = 450/(9.8*sin(radians(28))) = 97.8 kg. ANS.
The component of his weight perpendicular to the roof = Weight*cos28
450 = Weight*cos28
Weight = 450/cos28 = 510N
Mass = 510/9.8 = 52kg