A tank of nitrogen gas contains 9.365 L at a pressure of 7.342 atm and a temperature of 94.8 °C. Calculate?
4. A tank of nitrogen gas contains 9.365 L at a pressure of 7.342 atm and a temperature of 94.8 °C. Calculate the number of moles of nitrogen in the tank.
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Verified answer
PV = nRT
Using SI units throughout:
R = 8.314 J·K−1·mol−1
P = 7.324 atm = 7.324*101.3kPa = 741.9 kPa
V = 9.365 L = 9.365*10^-3 m^3
So:
741.9*10^3*9.365*10^-3 = n*8.314*(273 + 94.8)
6948 = n*3057.9
n = 2.272 moles of Nitrogen
Assuming it as ideal gas
PV=nRT
n=PV/RT
P=7.342 atm
V=9.365 l
R=0.082 l atm k^-1 mol ^-1
T=94.8+273 K
just put these values in above equation and get the answer