A supertanker with the mass of 8.19 × 107 kg is moving with a constant velocity...?
A supertanker with the mass of 8.19 × 10^7 kg is moving with a constant velocity. Its engines generate a forward thrust of 3.20 × 10^5 N. Determine (a) the magnitude of the resistive force exerted on the tanker by the water and (b) the magnitude of the upward buoyant force exerted on the tanker by the water.
Need a little help on this one... F=MA??? Thanks!
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You can actually start with F = MA
but since the tanker is moving at a constant velocity then, its acceleration is zero. Therefore, the resistive force exerted by the water on the tanker is simply equal to the thrust generated by the engines,i.e.,
Force = 3.2 x 10^5 Newtons
The buoyant force is simply equal to
Fb = (8.19 x 10^7)(9.8)
Fb = 8.0262 x 10^8 Newtons
Hope this helps.
Since the tanker is not accelerating (constant velocity) then the resistive force equals the thrust from the engines.
Since the tanker is not sinking or rising, the buoyant force from the water equals the mass of the tanker times the gravitational acceleration.