A scuba tank contains 2.83×10−2 m3 of compressed air at an absolute pressure of 2.07×107 Pa.?
A scuba tank contains 2.83×10−2 m3 of compressed air at an absolute pressure of 2.07×107 Pa. If all this air is released with no change in temperature, so that it has a pressure of 1.01×105 Pa (standard atmospheric pressure), what volume does it occupy?
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Use the thermodynamics equation, pV = nRT, to solve this problem where p = pressure, V=volume, n=number of molecules, R= gas constant, T=temp.
On the right side of the equation, none of these values change so the left side, pV must always equal nRT. Since you have two sets of values for different conditions, you can set them equal to each other.
pV(1st condition) = nRT
pV(2nd condition) = nRT
pV(1st condition) = pV(2nd condition)
2.07X107Pa * 2.83X10-2 m3 = 1.01X105Pa * V
Solve for V to find the volume of the second condition.