360⁰ - 152⁰ = 208⁰
208⁰ / 2 = 104⁰
d² = 10² + 10² - 2 x 10 x 10 cos 104⁰
d = 13•8 cm_____longest diagonal
Like ted s said:
c^2 = 10^2 + 10^2 - 2*10*10*cos(180 - 76°)
c^2 = 100 + 100 - 200*cos(104°)
c = sqrt(200 - 200*cos(104°)), note that a length can't be negative
c =~ 19.732551840809705931751378688735
c² = 10² + 10² - 2 x 10 x 10 cos ( 180 - 76)°....find c
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360⁰ - 152⁰ = 208⁰
208⁰ / 2 = 104⁰
d² = 10² + 10² - 2 x 10 x 10 cos 104⁰
d = 13•8 cm_____longest diagonal
Like ted s said:
c^2 = 10^2 + 10^2 - 2*10*10*cos(180 - 76°)
c^2 = 100 + 100 - 200*cos(104°)
c = sqrt(200 - 200*cos(104°)), note that a length can't be negative
c =~ 19.732551840809705931751378688735
c² = 10² + 10² - 2 x 10 x 10 cos ( 180 - 76)°....find c