A quarterback throws the football to a stationary receiver who is 30 m down the field.?
The football is thrown at an initial angle of
39.2 to the ground.
The acceleration of gravity is 9.81 m/s^2
a) At what initial speed must the quarterback throw the ball for it to reach the receiver?
Answer in units of m/s
b) What is the ball’s highest point during its
flight?
Answer in units of m
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Answers & Comments
Verified answer
To find the initial velocity, use this equation: R = (V^2Sin 2 theta)/g where R is the horizontal range = 30 , theta = 39.2
30 =( V^2 Sin 78.4)/9.81 =300.46 and V = 17.33
Vy = 17.33 Sin 39.2= 10.95m/s
Time to peak Height: V= Vyo - gt
0 = 10.95 - 9.81 t and t = 1.115 s
Max Height = S = Vyo t - 1/2 g t^2 = 10.95 x 1.115 - 4.9 (1.115)^2 = 6.1 m
Football Stationary