A projectile is launched with a speed of 36 m/s at an angle of 59° above the horizontal. Use conservation of energy to find the maximum height reached by the projectile during its flight.
Answer in (m)
Consider only vertical velocity = 36sin59
mgh = 1/2mv^2
h = 0.5v^2/g = 0.5*36sin59^2/9.8 = 48.5825m
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