A ladder 12 ft long leans against a building. The ladder forms an angle of 60° with the ground.?
(a) How high up the side of the building does the ladder reach? [Here and in part (b), give two forms for your answers: one with radicals and one (using a calculator) with decimals, rounded to two places.]
______ ft ≈ _________ft
(b) Find the horizontal distance from the foot of the ladder to the base of the building.
________ ft ≈ _________ft
I know how to find the ft rounded to the decimal places but i dont know how to find it in radians?
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In a 30-60-90 triangle, the side between the 60° and 90° angles (which in this case is the ground) is x in length. The side between the 30° and 90° angles (the side of the building) is x√3 in length. The side between the 30° and 60° angles (the ladder) is 2x in length. In this problem, the ladder 2x is equal to 12 feet, so x = 6.
(a) Side of building = 6√3 feet ≈ 10.39 feet
(b) Ground = 6 feet
Drawing a image constantly enables. yet once you positioned it up as a triangle you recognize the different factor of the attitude and would discover the hypotenuse. so so which you are able to use the SIN function. So it would be SIN(60deg) = 24/H. applying algebra it would finally end up that H (or the dimensions of the ladder) is 24/SIN60 that's..... 27.7128... or 16sqrt3