A kicked soccer ball has an initial velocity of 25 meters per second at an angle of 40.° above the horizontal,?
A kicked soccer ball has an initial velocity of 25 meters per second at an angle of 40.° above the horizontal, level ground. [Neglect friction.] Calculate the maximum height the ball reaches above its initial position.
The correct answer is 13.
I did 25 sin40 and got 16, but that's wrong because I didn't factor in gravity.
Thanks
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Well, you should really learn this on your own because you will need to know this on the test. But since you already know the awnser
You did find the force in the y direction correctly, good job, that's probably the hardest part.
First you have to find the time it takes to reach the maximum height. its derived from this equation v = v0 sin α − g t you kind of have to modify it to get to this t= vo * sin (a) / g
you should then have (25 m / s * sin40)/9.81 m/s/s since your dividing m/s by m/s/s your answer should come out to be in seconds right? approximately 1.63976 seconds right?
they you can use y=1/2g((1.63976)^2) and you should get 13.1752 assuming gravity = 9.81m/s^2