If the temperature of glass and water is decreased to 20.0 ∘C, how much water could be added to the glass?
Coefficient of linear expansion for Water: 210*10^-6
Coefficient of linear expansion for Water: 9*10^-6
I've tried everything and tried looking up how to do it as well, but no one has gotten the answer right. Please help!!!
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Verified answer
The change in the units volume when temperature change can be expressed as
dV = V0 β (t1 - t0) (2)
where
dV = V1 - V0 = change in volume L
β = volumetric temperature expansion coefficient (m3/m3 oC)
t1 = final temperature (oC)
t0 = initial temperature (oC)
dv = 440 10^-3* 210 * 10 ^ -6 ( 20 - 100 )
dv = 7.392 10^-3 L = - 7.392 mL
how much water could be added to the glass 7.392 mL
http://www.engineeringtoolbox.com/volumetric-tempe...
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