you have an easy ratio situation, applying the formulation P1V1/T1 = P2V2/T2 Now the P time era drops out, and additionally you desire to rework Celsius to Kelvin temperature. you're fixing for T2.
This relationship is defined in Charles' Law which states V1/T1 = V2/T2
Now, lets establish what we know, keeping in mind, temperature values must be in °K (°K=°C+273)
V1=4.10L
T1=338°K
V2=4.01L
T2=???
Now lets substitute the values that we know:
[(4.10L)/(338°K)=(4.01L)/(T2)
Now solve, and we are left with: T2=330.580°K
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you have an easy ratio situation, applying the formulation P1V1/T1 = P2V2/T2 Now the P time era drops out, and additionally you desire to rework Celsius to Kelvin temperature. you're fixing for T2.
This relationship is defined in Charles' Law which states V1/T1 = V2/T2
Now, lets establish what we know, keeping in mind, temperature values must be in °K (°K=°C+273)
V1=4.10L
T1=338°K
V2=4.01L
T2=???
Now lets substitute the values that we know:
[(4.10L)/(338°K)=(4.01L)/(T2)
Now solve, and we are left with: T2=330.580°K