A fixed quantity of gas at 23∘C exhibits a pressure of 757torr and occupies a volume of 5.42L .?
A fixed quantity of gas at 23∘C exhibits a pressure of 757torr and occupies a volume of 5.42L .
Calculate the volume the gas will occupy if the pressure is increased to 1.89atm while the temperature is held constant.
Calculate the volume the gas will occupy if the temperature is increased to 155∘C while the pressure is held constant.
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757 torr = 0.99605 atm
(5.42 L) x (0.99605 atm / 1.89 atm) = 2.86 L
Supposing the increase in temperature starts from the initial pressure:
(5.42 L) x (155 + 273) / (23 + 273) = 7.84 L
Hello Omar : The equation shown below is great for these problems :
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( P2 ) ( V2 ) / ( T2 ) = ( P1 ) ( V1 ) / ( T1 )
V2 = ( V1 ) ( P1 / P2 ) ( T2 / T1 )
This equation comes from the Ideal Gas Law and requires use of
absolute temperatures and absolute pressures.
The mass or moles of gas must remain constant.
For P2 = 1.89 atm :
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V2 = ( 5.42 L ) ( 1.89 atm / ( 757/760 atm) ( 296.2 / 296.2 )
V2 = 10.28 L <------------------------------------------------------------------------------
For T2 = 155 C :
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V2 = ( V1 ) ( P1 / P2 ) ( T2 / T1 )
V2 = ( 5.42 L ) ( 757 torr / 757 torr ) ( 428.2 / 296.2 )
V2 = 7.835 L <---------------------------------------------