A fire hose ejects a stream of water at an angle of 31.5° above the horizontal. The water leaves...?
A fire hose ejects a stream of water at an angle of 31.5° above the horizontal. The water leaves the nozzle with a speed of 21.0 m/s. Assuming that the water behaves like a projectile, how far from a building should the fire hose be located to hit the highest possible fire?
Update:Answer in meters.
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Using the max range equation .. R = u².sin2θ = g
R = (21)² x sin(2 x 31.5) / 9.80 .. .. R = 40.10m
Max height occurs at the mid point of the range distance ..
.. D = ½ 40.10m .. .. ►D = 20.05 m
Initial projectile (water) speed = Vo = 21.0 m/s
initial VERTICAL water speed = Voy = Vo(sin 31.5°) = 21(sin 31.5) = 10.97 m/s
initial HORIZONTAL water speed = Vox = Vo(cos 31.5°) = 21(cos 31.5) = 17.91 m/s
time to reach max height = t = Voy/g = 10.97/9.81 = 1.12 s
HORIZONTAL distance = Vox(t) = 17.91(1.12) = 20.0 m ANS