the probability of at least one​ head = 1 - Pr(X=0)

P(no heads) = (1/2)^5 = 1/32

P(1+ heads) = 31/32 = 0.96875

Rounds to 0.9688

50/50 every time you toss it. No matter how many times you toss it. Every time the odds are even.

Or just 1 minus the probability of 0 heads = 1 - (1/2)^5 = 1 - 0.03125 = 0.96875 = 96.875% or as a rounded decimal, 0.9688

P(1) = 1/2

P(2) = 1/4

P(3) = 1/8

P(4) = 1/16

P(5) = 1/32

P(at least one head) = 1/2 + 1/4 + 1/8 + 1/16 + 1/32 = 0.96875 or 96.875%