convert 157° to radians and multiply that by 5
2pi * 5 * (157/360) = 13.7ft
L arc = (157/360) x ( 2π x 5 ) ft
L arc = 13 . 7 ft
An arc with radius r and angle θ has the arc length:
s = rθ .... if θ is measured in radians, or
s = (θ/180)πr .... if θ is measured in degrees
Remember those two formulas (or just the second if you haven't studied radians yet.)
You have θ=157° and r=10 ft, so:
s= (157/180)π(5 ft) = 157π / 36 ft
That's exact, if the given measurements are, or about 13.7 ft using a calculator.
The circumference is 10 pi ft.
The specified arc has a length of
(10 pi ft)*(157/360) = 13.7 feet.
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Answers & Comments
convert 157° to radians and multiply that by 5
2pi * 5 * (157/360) = 13.7ft
L arc = (157/360) x ( 2π x 5 ) ft
L arc = 13 . 7 ft
An arc with radius r and angle θ has the arc length:
s = rθ .... if θ is measured in radians, or
s = (θ/180)πr .... if θ is measured in degrees
Remember those two formulas (or just the second if you haven't studied radians yet.)
You have θ=157° and r=10 ft, so:
s= (157/180)π(5 ft) = 157π / 36 ft
That's exact, if the given measurements are, or about 13.7 ft using a calculator.
The circumference is 10 pi ft.
The specified arc has a length of
(10 pi ft)*(157/360) = 13.7 feet.