A charged particle with a charge-to-mass ratio of |q|/m = 5.7 × 108 C/kg travels on a circular path that is perpendicular to a magnetic field whose magnitude is 0.74 T. How much time does it take for the particle to complete one revolution?
t = __________ s
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Verified answer
F centripetal = F magnetic
mv²/R = B q v
v = Bq/mR
For a circle :
v = 2 pi R /T = BqR/m
T = 2 pi m/Bq = 2 pi /(0.74 *5.7 × 108 C/kg) = 1.5 10^-8 s