A Carnot engine takes in heat from a reservoir at 470°C and releases heat to a lower-temperature reservoir at 120°C.
What is its efficiency?
__%
Efficiency η = (Thot-Tcold)/Thot
These temperatures are in degrees Kelvin.
Thus η = (470-120)/(470+273.15) = 0.471
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
Efficiency η = (Thot-Tcold)/Thot
These temperatures are in degrees Kelvin.
Thus η = (470-120)/(470+273.15) = 0.471