A car is parked on a cliff overlooking the ocean on an incline that makes an angle of 17.0° below the horizont?
A car is parked on a cliff overlooking the ocean on an incline that makes an angle of 17.0° below the horizontal. The negligent driver leaves the car in neutral, and the emergency brakes are defective. The car rolls from rest down the incline with a constant acceleration of 2.75 m/s2 for a distance of 30.0 m to the edge of the cliff. The cliff is 35.0 m above the ocean.
(a) Find the car's position relative to the base of the cliff when the car lands in the ocean
m
(b) Find the length of time the car is in the air.
s
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Verified answer
v = √(2as) = √(2 * 2.75m/s² * 30m) = 12.8 m/s
which has components Vx = 12.8m/s * cos-17º = 12.3 m/s
and Vy = 12.8m/s * sin-17º = -3.8 m/s
To fall to the ocean: s = So + Vo*t + ½at²
0 = 35 - 3.8t - 4.9t²
t = -3.1 s, 2.3 s ← take positive root.
So the distance from the cliff was x = Vx * t = 12.3m/s * 2.3s = 28.3 m
(b) Done; t = 2.3 s