dQ = m*cp*dT where m = mass of block, cp = specific heat of iron and dT = temperature change.
dQ = 3.5 10^4 J
cp = 0.45 Kj / Kg = 450 J / Kg
3.5 10^4 = 2.3 * 450 * dt --- dt = 35000 / 450 * 2.3 = 33.8 °
Final temperature = 34 + 33.8 = 67.8 °C
Goodbye
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
dQ = m*cp*dT where m = mass of block, cp = specific heat of iron and dT = temperature change.
dQ = 3.5 10^4 J
cp = 0.45 Kj / Kg = 450 J / Kg
3.5 10^4 = 2.3 * 450 * dt --- dt = 35000 / 450 * 2.3 = 33.8 °
Final temperature = 34 + 33.8 = 67.8 °C
Goodbye