You should INSTANTLY recognize a 3,4,5 triangle. So the other side has a magnitude of 7.5 km
But if you don't then you can resort to Pythagoras' theorem which is the standard method for all vector synthesis.
c = sqrt( a^2 + b^2 ) = sqrt( 4.5^2 + 6^2) = ( insert drum roll here ) 7.5 km
Now you can see that the angle will be south of west.
to get the angle you use tan(theta) = opposite /adjacent
theta = atan( 6/4.5) = atan (4/3) = 53 degrees South of West
Since south and west are perpendicular to each other, we can use the Pythagorean theorem to determine the magnitude of this velocity.
Speed = √(4.50^2 + 6.00^2) = 7.5 km
Tan θ = 6 ÷ 4.5 = 1⅓
The angle is approximately 53˚ south of west or 37 west of south. This is 3,4,5 right triangle.
using a vector calculator and compass directions
[4.50 km , 270°] + [6.00 km , 180°] = [ 7.5 km , 216.9°]
or
7.5 km at 36.9° west of south
When you get a good response,
please consider giving a best answer.
This is the only reward we get.
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
You should INSTANTLY recognize a 3,4,5 triangle. So the other side has a magnitude of 7.5 km
But if you don't then you can resort to Pythagoras' theorem which is the standard method for all vector synthesis.
c = sqrt( a^2 + b^2 ) = sqrt( 4.5^2 + 6^2) = ( insert drum roll here ) 7.5 km
Now you can see that the angle will be south of west.
to get the angle you use tan(theta) = opposite /adjacent
theta = atan( 6/4.5) = atan (4/3) = 53 degrees South of West
Since south and west are perpendicular to each other, we can use the Pythagorean theorem to determine the magnitude of this velocity.
Speed = √(4.50^2 + 6.00^2) = 7.5 km
Tan θ = 6 ÷ 4.5 = 1⅓
The angle is approximately 53˚ south of west or 37 west of south. This is 3,4,5 right triangle.
using a vector calculator and compass directions
[4.50 km , 270°] + [6.00 km , 180°] = [ 7.5 km , 216.9°]
or
7.5 km at 36.9° west of south
When you get a good response,
please consider giving a best answer.
This is the only reward we get.