Verified answer

Use Charles' Law since pressure is constant: V1/T1 = V2/T2

Find the temperature in kelvins first.

T1= 35°C +273.15= 308 K

T2= -196°C + 273.15 = 77 K

V1=2.10 L

V2= x

Plug into the equation

2.10 L/ 308 K = x / 77 K

cross multiply

160 L*K = 308 K *x

divide 308 K over

x=0.52 L

The cooled balloon has a volume of 0.52 Liters,

This is a Charles' law application: V₁/T₁ = V₂/T₂. Remember that temperatures must be expressed in Kelvins - K = °C + 273. 35°C = 308 K; -196°C = 77-K. Charles' law states that the volume of a confined gas is directly proportional to its Kelvin temperature.

2.10-L / 308-K = V₂/77-K ===> V₂ = 0.525-L

In this problem, the temperature decreases from 308-K to 77-K - a four-fold decrease (308/77=4). This means that the volume should also experience a four-fold decrease. 2.10/4 = 0.525