A 555 g piece of copper tubing is heated to 96.8.°C and placed in an insulated vessel containing 54.0 g of?
water at 36.5°C. Assuming no loss of water and heat capacity for the vessel of 10.0 J/K, what is the final temperature of the system (c of copper = 0.387 J/g·K)?
°C
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Since there are no phase changes going on, this is all just sensible heats, MCDeltaT
So the heat lost by the hot copper equals the heat gained by the water and the vessel.
Heat lost by copper =
[96.8 - TF] x 555 x .387 J
Heat gained by water and vessel =
[TF -36.5] x 54 x 4.184 + [TF -36.5] x 10
Equate those and solve for TF