A 50.0 gram sample of tungsten loses 5,687 J of energy and ends up with a temperature of 145.0 ◦C. What was its initial temperature?
Update:
(c = 0.134 J/g◦C)
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(c = 0.134 J/g◦C)
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If the start temperature is X °C then the temperature change, ΔT, is:
ΔT = X - 145.0
Q = mcΔT
5687 = 50.0 * 0.134 * (X - 145.0)
(X - 145.0) = 5687 / (50.0 * 0.134)
. . . . . . . . . = 848.8
X = 848.8 + 145.0
. . = 993.8°C
cs (specific heat capacity) of tungsten = 130 J/kgK
ΔΤ = Q/(m*cs) = 5687/(50.0*10^-3*130) = 874,9 °C
T = 145.0 + 874.9 = 1019.9 °C