A 295 mL sealed container at 25 °C contains 0.80 g of a gas at 680 torr. What is the molar mass of the gas?
A 295 mL sealed container at 25 °C contains 0.80 g of a gas at 680 torr. What is the molar mass of the gas?
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PV = nRT
n = PV/RT = (680 torr) x (0.295 L) / ((62.36367 L Torr /K mol) x (25 + 273 K)) = 0.010794 mol
(0.80 g) / (0.010794 mol) = 74 g/mol