What was the average force applied by the ball on the glove?
Given,
mass (m) = 149 grams = 0.149kg
Initial velocity (u) = 41.9m/sec
final velocity (v) = 0m/sec
distance (s)= 2cm = 0.02m
force (F)= ?
We know that:-
force (F)= mass*Acceleration
using Kinematic relation:-
v2-u2 = -2as
Acceleration (a) = v2-u2/-2s
= 02-(41.9)2/-2*0.02
= -1755.61/-0.04
= 43890.25
Acceleration (a) = 43890.25m/s2
Now,
force (F) = mass*Acceleration
= 0.149*43890.25
= 6539.6
≈ 6540N
force (F) = 6540N
v^2 = u^2 - 2as
0 = u^2 - 2as
a = u^2/2s
= 41.9^2/2(0.02)
F = 0.149 x 43890.25
= 6539.64725
= 6539.65 N
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Answers & Comments
Given,
mass (m) = 149 grams = 0.149kg
Initial velocity (u) = 41.9m/sec
final velocity (v) = 0m/sec
distance (s)= 2cm = 0.02m
force (F)= ?
We know that:-
force (F)= mass*Acceleration
using Kinematic relation:-
v2-u2 = -2as
Acceleration (a) = v2-u2/-2s
= 02-(41.9)2/-2*0.02
= -1755.61/-0.04
= 43890.25
Acceleration (a) = 43890.25m/s2
Now,
force (F) = mass*Acceleration
= 0.149*43890.25
= 6539.6
≈ 6540N
force (F) = 6540N
v^2 = u^2 - 2as
0 = u^2 - 2as
a = u^2/2s
= 41.9^2/2(0.02)
= 43890.25
F = 0.149 x 43890.25
= 6539.64725
= 6539.65 N