A 0.43-µC particle moves with a speed of 16 m/s through a region where the magnetic field has a strength of 0.?

A 0.43-µC particle moves with a speed of 16 m/s through a region where the magnetic field has a strength of 0.90 T. At what angle (counterclockwise from the +x-axis) to the field is the particle moving if the following forces are exerted on it?

(a) 4.8 10−6 N

Work:

sinθ = F/qvB

sinθ = (4.8*10^-6 N)/[(4.3*10^-7 C)(16 m/s)(0.9 T) =0.755

I'm just not sure how to convert that to degrees. Please and thank you :)

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