√63/3 + 14/√7 in the form n√7 where n is an integer, anyone wanna help out here? Would be much appreciated!
-Max
√63 = √9 * √7 = 3√7. So, (√63)/3 = √7.
To simplify 14/√7, multplify numerator and denominator by √7. This gives you (14√7)/7 = 2√7.
So, your equation equals √7 + 2√7 = 3√7
n = 3.
get them to have the same denominator : 3 root 7
add the numerator
simplify
multiply both denominator and numberator by root 7
** im assuming that only 63 is rooted and not 63/3 (in the question)
n=15
(63^.5)/3 + 14(7^.5)
= (9^.5)(7^.5)/3 + 14(7^.5)
=3(7^.5)/3 + 14(7^.5)
= 15(7^.5)
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Verified answer
√63 = √9 * √7 = 3√7. So, (√63)/3 = √7.
To simplify 14/√7, multplify numerator and denominator by √7. This gives you (14√7)/7 = 2√7.
So, your equation equals √7 + 2√7 = 3√7
n = 3.
get them to have the same denominator : 3 root 7
add the numerator
simplify
multiply both denominator and numberator by root 7
** im assuming that only 63 is rooted and not 63/3 (in the question)
n=15
(63^.5)/3 + 14(7^.5)
= (9^.5)(7^.5)/3 + 14(7^.5)
=3(7^.5)/3 + 14(7^.5)
= 15(7^.5)