5. How many grams of potassium chlorate decompose to potassium chloride and 638 mL of O2 at 128 ºC and 752 tor?
5. How many grams of potassium chlorate decompose to potassium chloride and 638 mL of O2 at 128 ºC and 752 torr?
2KClO3 (S)-->2KCl(S) + 3O2(g)
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You have to find out how many moles of O2 you have at that pressure and temp. Use PV=nRT. Then calculate grams from moles of KClO3.
Use the ideal gas laww to find moles of O2 formed.
PV = nRT
n = PV/ RT
n = (752/760 atm)(0.638 L) / (0.0821 L atm / K mole)(401 K) = 0.0192 moles O2
0.0192 moles O2 x (2 moles KClO3 / 3 moles O2) x (122.6 g KClO3 / 1 mole KClO3) =
1.57 g KClO3